JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा Question Bank ac Circuits

  • question_answer
    In the circuit shown below, the ac source has voltage \[V=20\cos (\omega t)\] volts with \[\omega \]= 2000 rad/sec. the amplitude of the current will be nearest to  [AMU (Engg.) 2000]

    A)            \[2A\]

    B)            \[3.3A\]

    C)            \[2/\sqrt{5}A\]

    D)            \[\sqrt{5}A\]

    Correct Answer: A

    Solution :

                       \[R=6+4=10\,\Omega \]                    \[{{X}_{L}}=\omega L=2000\times 5\times {{10}^{-3}}=10\,\Omega \]                    \[{{X}_{C}}=\frac{1}{\omega C}=\frac{1}{2000\times 50\times {{10}^{-6}}}=10\,\Omega \]                    \[\therefore \,\,Z=\sqrt{{{R}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}=10\,\Omega \]            Amplitude of current \[={{i}_{0}}=\frac{{{V}_{0}}}{Z}=\frac{20}{10}=2A\]


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