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JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा Question Bank ac Circuits

  • question_answer
    A circuit has a resistance of \[11\Omega ,\] an inductive reactance of \[25\Omega \] and a capacitative resistance of \[18\Omega .\] It is connected to an ac source of 260V and 50Hz. The current through the circuit (in amperes) is                               [Kerala PMT 2002]

    A)            11  

    B)            15

    C)            18  

    D)            20

    Correct Answer: D

    Solution :

                       \[Z=\sqrt{{{R}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}=\sqrt{{{(11)}^{2}}+{{(25-18)}^{2}}}=13\,\Omega \]            Current \[i=\frac{260}{13}=20\,A\]


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