JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा Question Bank ac Circuits

  • question_answer
    An inductor of inductance L and resistor of resistance R are joined in series and connected by a source of frequency \[\omega \]. Power dissipated in the circuit is [AIEEE 2002; RPET 2003]

    A)            \[\frac{({{R}^{2}}+{{\omega }^{2}}{{L}^{2}})}{V}\]  

    B)            \[\frac{{{V}^{2}}R}{({{R}^{2}}+{{\omega }^{2}}{{L}^{2}})}\]

    C)            \[\frac{V}{({{R}^{2}}+{{\omega }^{2}}{{L}^{2}})}\]  

    D)            \[\frac{\sqrt{{{R}^{2}}+{{\omega }^{2}}{{L}^{2}}}}{{{V}^{2}}}\]

    Correct Answer: B

    Solution :

               \[P=Vi\cos \varphi =V\ \left( \frac{V}{Z} \right)\ \left( \frac{R}{Z} \right)=\frac{{{V}^{2}}R}{{{Z}^{2}}}\]\[=\frac{{{V}^{2}}R}{({{R}^{2}}+{{\omega }^{2}}{{L}^{2}})}\]


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