A) \[9.8\,m/{{\sec }^{2}}\]
B) \[4.9\,m/{{\sec }^{2}}\]
C) \[980\,m/{{\sec }^{2}}\]
D) \[19.6\,m/{{\sec }^{2}}\]
Correct Answer: B
Solution :
\[\frac{g'}{g}=\frac{M'}{M}{{\left( \frac{R}{R'} \right)}^{2}}=\left( \frac{2M}{M} \right)\ {{\left( \frac{R}{2R} \right)}^{2}}=\frac{1}{2}\] Þ\[{g}'=\frac{g}{2}=\frac{9.8}{2}=4.9\ m/{{s}^{2}}\]
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