A) \[4\pi G/3gR\]
B) \[3\pi R/4gG\]
C) \[3g/4\pi RG\]
D) \[\pi RG/12G\]
Correct Answer: C
Solution :
\[g=\frac{GM}{{{R}^{2}}}\] and \[M=\frac{4}{3}\pi {{R}^{3}}\times \rho \] \[\therefore \,\,g=\frac{4}{3}\frac{\pi {{R}^{3}}\times GD}{{{R}^{2}}}\,\Rightarrow \,D=\frac{3g.}{4\pi RG}\]
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