JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Acceleration Due to Gravity

  • question_answer
    The value of g on the earth's surface is \[980\,cm/{{\sec }^{2}}\]. Its value at a height of 64 km from the earth's surface is [MP PMT 1995]

    A)             \[960.40\,cm/{{\sec }^{2}}\]

    B)               \[984.90\,cm/{{\sec }^{2}}\]

    C)             \[982.45\,cm/{{\sec }^{2}}\]           

    D)             \[977.55\,cm/{{\sec }^{2}}\]

    Correct Answer: A

    Solution :

                    \[\frac{g'}{g}={{\left( \frac{R}{R+h} \right)}^{2}}={{\left( \frac{6400}{6400+64} \right)}^{2}}\]\[\Rightarrow \]\[g'=960.40\ cm/{{s}^{2}}\]


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