A) \[\frac{1}{4}R\]
B) R
C) \[\frac{3}{8}R\]
D) \[\frac{R}{2}\]
Correct Answer: B
Solution :
\[g'=g{{\left( \frac{R}{R+h} \right)}^{2}}\]Þ \[\frac{g}{4}=g{{\left( \frac{R}{R+h} \right)}^{2}}\]Þ \[\frac{1}{2}=\frac{R}{R+h}\] Þ\[R+h=2R\]\ \[h=R\]You need to login to perform this action.
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