A) \[2.5\times {{10}^{-3}}rad/s\]
B) \[5.0\times {{10}^{-1}}rad/s\]
C) \[10\times {{10}^{1}}rad/s\]
D) \[7.8\times {{10}^{-2}}rad/s\]
Correct Answer: A
Solution :
\[{g}'=g-{{\omega }^{2}}R{{\cos }^{2}}\lambda \]Þ\[0=g-{{\omega }^{2}}R{{\cos }^{2}}{{60}^{o}}\] \[0=g-\frac{{{\omega }^{2}}R}{4}\,\Rightarrow \,\omega =2\sqrt{\frac{g}{R}}=\frac{1}{400}\frac{rad}{\sec }\] \[=2.5\times {{10}^{-3}}\frac{rad}{sec}\]
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