JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Acceleration Due to Gravity

  • question_answer
    R and r are the radii of the earth and moon respectively. \[{{\rho }_{e}}\] and \[{{\rho }_{m}}\] are the densities of earth and moon respectively. The ratio of the accelerations due to gravity on the surfaces of earth and moon is [EAMCET 2000]

    A) \[\frac{R}{r}\frac{{{\rho }_{e}}}{{{\rho }_{m}}}\]

    B)   \[\frac{r}{R}\frac{{{\rho }_{e}}}{{{\rho }_{m}}}\]

    C)             \[\frac{r}{R}\frac{{{\rho }_{m}}}{{{\rho }_{e}}}\]          

    D)             \[\frac{R}{r}\frac{{{\rho }_{e}}}{{{\rho }_{m}}}\]

    Correct Answer: A

    Solution :

        \[g=\frac{4}{3}\pi \rho GR\]\\[g\propto r\rho \]\ \[\frac{{{g}_{e}}}{{{g}_{m}}}=\frac{R}{r}\times \frac{{{\rho }_{e}}}{{{\rho }_{m}}}\]


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