JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Acceleration Due to Gravity

  • question_answer
    Assume that the acceleration due to gravity on the surface of the moon is 0.2 times the acceleration due to gravity on the surface of the earth. If \[{{R}_{e}}\] is the maximum range of a projectile on the earth?s surface, what is the maximum range on the surface of the moon for the same velocity of projection   [Kerala (Engg.) 2001]

    A)             \[0.2\,{{R}_{e}}\]     

    B)             \[2\,{{R}_{e}}\]

    C)             \[0.5\,{{R}_{e}}\]     

    D)             \[5\,{{R}_{e}}\]

    Correct Answer: D

    Solution :

                    Range of projectile\[R=\frac{{{u}^{2}}\sin 2\theta }{g}\] if u and q are constant then \[R\propto \frac{1}{g}\]             \[\frac{{{R}_{m}}}{{{R}_{e}}}=\frac{{{g}_{e}}}{{{g}_{m}}}\Rightarrow \frac{{{R}_{m}}}{{{R}_{e}}}=\frac{1}{0.2}\Rightarrow {{R}_{m}}=\frac{{{R}_{e}}}{0.2}\]Þ \[{{R}_{m}}=5{{R}_{e}}\]


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