JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Acceleration Due to Gravity

  • question_answer
    The angular speed of earth, so that the object on equator may appear weightless, is \[(g=10\,m/{{s}^{2}}\], radius of earth 6400 km)                                    [Pb. PMT 2001]

    A)             \[1.25\times {{10}^{-3}}rad/sec\]

    B)               \[1.56\times {{10}^{-3}}rad/sec\]

    C)             \[1.25\times {{10}^{-1}}rad/sec\]   

    D)             1.56 rad/sec

    Correct Answer: A

    Solution :

        For condition of weightlessness of equator \[\omega =\sqrt{\frac{g}{R}}=\frac{1}{800}=1.25\times {{10}^{-3}}\frac{rad}{s}\]


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