A) 2 R
B) R
C) 1.414 R
D) 0.414 R
Correct Answer: D
Solution :
\[g'=g\,{{\left( \frac{R}{R+h} \right)}^{2}}\,\Rightarrow \,\frac{1}{\sqrt{2}}=\frac{R}{R+h}\] Þ \[R+h=\sqrt{2}\,R\]\[\Rightarrow \,h=(\sqrt{2}-1)R=0.414\,R\]
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