A) \[\frac{g}{{{\left( 1+\frac{h}{R} \right)}^{2}}}\]
B) \[g\left( 1-\frac{2h}{R} \right)\]
C) \[\frac{g}{{{\left( 1-\frac{h}{R} \right)}^{2}}}\]
D) \[g\left( 1-\frac{h}{R} \right)\]
Correct Answer: A
Solution :
\[{g}'=g\,{{\left( \frac{R}{R+h} \right)}^{2}}=\frac{g}{{{\left( 1+\frac{h}{R} \right)}^{2}}}\]
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