JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Acceleration Due to Gravity

  • question_answer
    The acceleration due to gravity near the surface of a planet of radius R and density d is proportional to [MP PET 2002; AIEEE 2004]

    A)             \[\frac{d}{{{R}^{2}}}\]     

    B)             \[d{{R}^{2}}\]

    C)             dR       

    D)             \[\frac{d}{R}\]

    Correct Answer: C

    Solution :

                    \[g=\frac{4}{3}\pi \rho GR\,\Rightarrow \,g\propto dR\]        \[(\rho =d\ \text{given in the problem)}\]


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