A) 0.2 g
B) 0.4 g
C) 2 g
D) 4 g
Correct Answer: A
Solution :
\[\ g=\frac{4}{3}\pi GR\rho \] and \[{g}'=\frac{4}{3}\pi G{R}'\rho \] \ \[\frac{{{g}'}}{g}=\frac{{{R}'}}{R}=0.2\] Þ \[{g}'=0.2\,g\]You need to login to perform this action.
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