A) R
B) \[\frac{3R}{4}\]
C) \[11.2\times {{10}^{2}}\,km{{s}^{-1}}\]
D) \[\frac{R}{4}\]
Correct Answer: B
Solution :
\[g'=g\,\left( 1-\frac{d}{R} \right)\Rightarrow \frac{g}{4}=g\,\left( 1-\frac{d}{R} \right)\,\Rightarrow d=\frac{3}{4}R\]
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