JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Acceleration Due to Gravity

  • question_answer
     What should be the angular speed of earth, so that body lying on equator may appear weightlessness             \[(g=10\,m/{{s}^{2}},\,\,R=6400\,km)\]                       [Pb. PET 2000]

    A)             \[\frac{1}{800}rad/s\]

    B)               \[\frac{1}{400}rad/s\]

    C)             \[\frac{1}{600}rad/s\]

    D)               \[\frac{1}{100}rad/s\]

    Correct Answer: A

    Solution :

                    \[{g}'=g-{{\omega }^{2}}R{{\cos }^{2}}\lambda \] For weightlessness at equator \[\lambda =0{}^\circ \] and \[g'=0\] \ \[0=g-{{\omega }^{2}}R\]Þ \[\omega =\sqrt{\frac{g}{R}}=\frac{1}{800}\frac{rad}{\sec }\]


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