JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Acceleration of Simple Harmonic Motion

  • question_answer
    A particle executes harmonic motion with an angular velocity and maximum acceleration of 3.5 rad/sec and 7.5 m/s2 respectively. The amplitude of oscillation is [AIIMS 1999; Pb. PET 1999]

    A)            0.28 m                                     

    B)            0.36 m

    C)            0.53 m                                     

    D)            0.61 m

    Correct Answer: D

    Solution :

               \[{{A}_{\max }}=a{{\omega }^{2}}\Rightarrow a=\frac{{{A}_{\max }}}{{{\omega }^{2}}}=\frac{7.5}{{{(3.5)}^{2}}}=0.61\ m\]


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