A) \[10\,\,m/{{s}^{2}}\]
B) \[10\,\pi \,m/{{s}^{2}}\]
C) \[\frac{10\pi }{2}\,m/{{s}^{2}}\]
D) \[\frac{10\pi }{3}\,m/{{s}^{2}}\]
Correct Answer: A
Solution :
\[a=10\times {{10}^{-2}}m\] and \[\omega =10\ rad/sec\] \[{{A}_{\max }}={{\omega }^{2}}a=10\times {{10}^{-2}}\times {{10}^{2}}=10\ m/{{\sec }^{2}}\]
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