JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Acceleration of Simple Harmonic Motion

  • question_answer
    A particle is executing simple harmonic motion with an amplitude of 0.02 metre and frequency 50 Hz. The maximum acceleration of the particle is    [MP PET 2001]

    A)            \[100\,\,m/{{s}^{2}}\]      

    B)            \[100\,{{\pi }^{2}}\,m/{{s}^{2}}\]

    C)            \[100\,\,m/{{s}^{2}}\]      

    D)            \[200\,{{\pi }^{2}}\,m/{{s}^{2}}\]

    Correct Answer: D

    Solution :

               \[{{A}_{\max }}=4{{\pi }^{2}}{{n}^{2}}a=4{{\pi }^{2}}\times {{(50)}^{2}}\times 0.02\]\[=200{{\pi }^{2}}m/s\]


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