JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Acceleration of Simple Harmonic Motion

  • question_answer
    A body executing simple harmonic motion has a maximum acceleration equal to \[24metres/se{{c}^{2}}\] and maximum velocity equal to \[16\ metres/sec\]. The amplitude of the simple harmonic motion is [MP PMT 1995; DPMT 2002; RPET 2003; Pb. PET 2004]

    A)            \[\frac{32}{3}metres\]     

    B)            \[\frac{3}{32}metres\]

    C)            \[\frac{1024}{9}metres\]

    D)            \[\frac{64}{9}metres\]

    Correct Answer: A

    Solution :

                       Maximum velocity \[=a\omega \]= 16 Maximum acceleration \[={{\omega }^{2}}a=24\] \[\Rightarrow a=\frac{{{(a\omega )}^{2}}}{{{\omega }^{2}}a}=\frac{16\times 16}{24}=\frac{32}{3}m\]


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