A) 25 N
B) 5 N
C) 2.5 N
D) 0.5 N
Correct Answer: D
Solution :
Maximum force \[=m(a{{\omega }^{2}})=ma\left( \frac{4{{\pi }^{2}}}{{{T}^{2}}} \right)\] \[=0.5\,\left( \frac{4{{\pi }^{2}}}{{{\pi }^{2}}/25} \right)\times 0.01=0.5N\]
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