A) A conjugate base
B) A non-polar solvent
C) An acid
D) A base
Correct Answer: C
Solution :
\[\underset{\text{Acid}}{\mathop{{{H}_{2}}O\,}}\,+\underset{\text{base}}{\mathop{N{{H}_{3}}}}\,\]⇌\[NH_{4}^{+}+O{{H}^{-}}\]. In this reaction \[{{H}_{2}}O\] acts as acid because it donate a proton.You need to login to perform this action.
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