A) Acidic
B) Basic
C) Neutral
D) Slightly basic
Correct Answer: A
Solution :
M.eq. of 0.2M \[{{H}_{2}}S{{O}_{4}}\]\[=\frac{2\times 0.2M}{1000}\times 100=0.04\] m/l M.eq. of .2M \[NaOH\]\[=\frac{0.2}{1000}\times 100=0.02\] m/l left \[[{{H}^{+}}]=.04-.02=.02\]. Total volume\[=200=\frac{.02}{200}=.0001={{10}^{-4}}\]M \[pH=4\].You need to login to perform this action.
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