A) 40 m/s N?W
B) \[20\sqrt{2}\,\]m/s N?W
C) 40 m/s S?W
D) \[20\sqrt{2}\] m/s S?W
Correct Answer: D
Solution :
From figure \[{{\overrightarrow{v}}_{1}}=20\hat{j}\] and \[{{\overrightarrow{v}}_{2}}=-20\hat{i}\] \[\Delta \overrightarrow{v}={{\overrightarrow{v}}_{2}}-{{\overrightarrow{v}}_{1}}=-20(\hat{i}+\hat{j})\] \[|\Delta \overrightarrow{v}|\,=\,20\sqrt{2}\]and direction \[\theta ={{\tan }^{-1}}(1)=45{}^\circ \] i.e. S?WYou need to login to perform this action.
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