JEE Main & Advanced Physics Vectors Question Bank Addition and Subtraction of Vectors

  • question_answer
    A particle has displacement of 12 m towards east and 5 m towards north then 6 m vertically upward. The sum of these displacements is                                               [AIIMS 1998]

    A)                 12          

    B)                 10.04 m

    C)                 14.31 m

    D)                 None of these

    Correct Answer: C

    Solution :

                        \[R=\sqrt{{{12}^{2}}+{{5}^{2}}+{{6}^{2}}}=\sqrt{144+25+36}=\sqrt{205}=14.31\ m\]


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