JEE Main & Advanced Physics Vectors Question Bank Addition and Subtraction of Vectors

  • question_answer
    Two forces, each of magnitude F have a resultant of the same magnitude F. The angle between the two forces is                 [CBSE PMT 1990]

    A)                 \[\text{45}{}^\circ \]      

    B)                 \[\text{12}0{}^\circ \]

    C)                 \[\text{15}0{}^\circ \]   

    D)                 \[\text{6}0{}^\circ \]

    Correct Answer: B

    Solution :

                        \[R=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos \theta }\] By substituting, \[A=F,\ B=F\] and \[R=F\] we get                 \[\cos \theta =\frac{1}{2}\therefore \theta =120{}^\circ \]


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