A) \[8{{P}_{o}}\]
B) \[16{{P}_{0}}\]
C) \[6{{P}_{o}}\]
D) \[2{{P}_{o}}\]
Correct Answer: B
Solution :
\[\frac{{{P}_{2}}}{{{P}_{1}}}={{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma }}\]Þ \[{{P}_{2}}={{P}_{1}}{{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma }}={{P}_{0}}{{(8)}^{4/3}}=16{{P}_{0}}.\]
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