A) 227.36 K
B) 500.30 K
C) 454.76 K
D) \[-{{47}^{o}}C\]
Correct Answer: A
Solution :
\[T{{V}^{\gamma -1}}=\]constant Þ \[\frac{{{T}_{2}}}{{{T}_{1}}}={{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma }}\]Þ \[{{T}_{2}}={{T}_{1}}{{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma }}\] \[\Rightarrow {{T}_{2}}=300{{\left( \frac{1}{2} \right)}^{0.4}}=227.36\ K\]
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