A) \[{{627}^{o}}C\]
B) \[{{527}^{o}}C\]
C) \[{{427}^{o}}C\]
D) \[{{327}^{o}}C\]
Correct Answer: D
Solution :
Using relation\[\frac{{{T}_{2}}}{{{T}_{1}}}={{\left( \frac{{{P}_{2}}}{{{P}_{1}}} \right)}^{\frac{\gamma -1}{\gamma }}}={{(8)}^{\frac{3/2-1}{3/2}}}=2\]. Þ \[{{T}_{2}}=2{{T}_{1}}\]Þ \[{{T}_{2}}=2\,(273+27)=600K=327{}^\circ C\]
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