JEE Main & Advanced Physics Thermodynamical Processes Question Bank Adiabatic Process

  • question_answer
    Air is filled in a motor tube at \[{{27}^{o}}C\] and at a pressure of \[8\] atmospheres. The tube suddenly bursts, then temperature of air is \[[\text{Given}\,\,\gamma \,\text{of}\,\text{air}=\,1.5]\]                                 [MP PMT 2002]

    A)            \[{{27.5}^{o}}C\]                

    B)            \[{{75}^{o}}K\]

    C)            \[150\,K\]                              

    D)            \[{{150}^{o}}C\]

    Correct Answer: C

    Solution :

                       \[\frac{{{T}_{2}}}{{{T}_{1}}}={{\left( \frac{{{P}_{2}}}{{{P}_{1}}} \right)}^{\frac{\gamma -1}{\gamma }}}\]\[\Rightarrow \frac{{{T}_{2}}}{{{T}_{1}}}={{\left( \frac{1}{8} \right)}^{\frac{1.5-1}{1.5}}}={{\left( \frac{1}{8} \right)}^{\frac{1}{3}}}=\frac{1}{2}\] \[\Rightarrow {{T}_{2}}=\frac{{{T}_{1}}}{2}=\frac{300}{2}=150K\].


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