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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Adiabatic Process

  • question_answer
    One mole of an ideal gas at an initial temperature of T K does 6 R joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5/3, the final temperature of gas will be  [CBSE PMT 2004]

    A)            \[(T+2.4)\,K\]                      

    B)            \[(T-2.4)\,K\]

    C)            \[(T+4)\,K\]                          

    D)            \[(T-4)\,K\]

    Correct Answer: D

    Solution :

               \[W=\frac{R({{T}_{i}}-{{T}_{f}})}{\gamma -1}\]Þ \[6R=\frac{R(T-{{T}_{f}})}{\left( \frac{5}{3}-1 \right)}\]Þ \[{{T}_{f}}=(T-4)K.\]


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