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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Adiabatic Process

  • question_answer
    One mole of an ideal gas with \[\gamma =1.4\], is adiabatically compressed so that its temperature rises from 27°C to 35°C. The change in the internal energy of the gas is \[(R=8.3\,J/mol.K)\]              [EAMCET 2001]

    A)            ?166 J                                      

    B)            166 J

    C)            ?168 J                                      

    D)            168 J

    Correct Answer: B

    Solution :

                       Change in internal energy of the gas            \[\Delta U=-\,\Delta W\frac{R}{\gamma -1}\left[ {{T}_{2}}-{{T}_{1}} \right]\]\[=\frac{8.3}{(1.4-1)}[308-300]=166J\]


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