JEE Main & Advanced Physics Thermodynamical Processes Question Bank Adiabatic Process

  • question_answer
    The volume of a gas is reduced adiabatically to \[\frac{1}{4}\] of its volume at 27°C, if the value of \[\gamma =1.4,\] then the new temperature will be                                                                           [DPMT 2000]

    A)            \[350\times {{4}^{0.4}}K\]     

    B)             \[300\times {{4}^{0.4}}\]K

    C)            \[150\times {{4}^{0.4}}\]K     

    D)            None of these

    Correct Answer: B

    Solution :

                       For adiabatic change \[T{{V}^{\gamma -1}}\]= constant                    Þ \[\frac{{{T}_{2}}}{{{T}_{1}}}={{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma -1}}\]Þ \[{{T}_{2}}={{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma -1}}\times {{T}_{1}}\]            Þ \[{{T}_{2}}={{\left( \frac{V}{V/4} \right)}^{1.4-1}}\times 300\] \[=300\times {{(4)}^{0.4}}K\]


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