A) 1
B) \[-2\frac{11}{4}\]
C) \[-\frac{11}{4}\]
D) \[2\frac{3}{4}\]
E) None of these
Correct Answer: D
Solution :
Explanation Option [d] is correct. We have, \[\frac{4y+1}{3}+\frac{2y-1}{2}-\frac{3y-7}{5}=6\Rightarrow \frac{40y+10+30y-15-18y+42}{30}=6\] \[\Rightarrow 52y+37=180\Rightarrow 52y=180-37\Rightarrow y=\frac{143}{52}=\frac{11}{4}\]You need to login to perform this action.
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