A) \[2,-\frac{1}{3}\]
B) \[3,-\frac{1}{2}\]
C) \[-3,\frac{1}{2}\]
D) \[-2,\frac{1}{3}\]
Correct Answer: B
Solution :
Put \[z=\frac{1}{y}\] in the given simultaneous equations they may be writ/ten as \[2x-3z=12\] ? (i) \[5x+7z=1\] ? (ii) Solving equations (i) and (ii), we get \[x=3,\,\,z=-2\] or \[x=3,\,\,y=\frac{1}{z}=-\frac{1}{2}\]You need to login to perform this action.
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