A) 1
B) 3
C) 4
D) 5
Correct Answer: D
Solution :
If \[x+2\] is a factor of\[f(x)={{(x+1)}^{5}}+{{(2x+K)}^{3}}\], then \[f(-2)=0\] or \[{{(-2+1)}^{5}}+{{[2\times (-2)+K]}^{3}}=0\] or \[-1+{{(K-4)}^{3}}=0\] or \[[(K-4)-1]{{(K-4)}^{2}}+1+(K-4)]=0\] or \[K=1\], as\[[{{(K-4)}^{2}}+1+(K-4)]\]does not give real value of\[K\].You need to login to perform this action.
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