A) 5
B) - 3
C) 0
D) 3
Correct Answer: D
Solution :
Since the equation \[4{{x}^{2}}+x(p+1)+1=0\] has two equal roots, therefore Discriminant\[=0\] or \[{{b}^{2}}-4ac=0\] or \[{{(p+1)}^{2}}-4\times 4\times 1=0\] or \[{{p}^{2}}+2p+1-16=0\] or \[{{p}^{2}}+2p-15=0\] or \[(p+5)(p-3)=0\] \[\therefore \] \[p=-5\]or\[p=3\] Hence, one of the values of \[p\] is\[3\].You need to login to perform this action.
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