A) 12
B) 12 and 24
C) 24
D) 36
Correct Answer: A
Solution :
If \[n\] is a whole number, then least value of\[n=2,\,\,3,\,\,4,\,\,....\] \[{{n}^{2}}({{n}^{2}}-1)={{n}^{2}}(n+1)(n-1)\] \[={{[4(2+1)(2-1)]}_{n=2}}\] \[=12\] Hence, the given expression is always divisible by\[12\].You need to login to perform this action.
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