A) \[\frac{1}{10}\]
B) 4
C) 2
D) \[\frac{1}{2}\]
Correct Answer: D
Solution :
Let the numbers are\[x\]and\[y\]. \[x+y=20\] and\[xy=40\] Sum of the reciprocal of the numbers \[x\] and \[y\] \[\frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}=\frac{20}{40}=\frac{1}{2}\]You need to login to perform this action.
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