A) a = 0
B) a = 1
C) a = 2
D) a = 3
Correct Answer: A
Solution :
Putting\[a=0\], we have given expression \[={{x}^{3}}-7x-6\] \[={{x}^{3}}-x-6x-6\] \[=x({{x}^{2}}-1)-6(x+1)\] \[=(x+1)[x(x-1)-6]\] \[=(x+1)[{{x}^{2}}-3x+2x-6]\] \[=(x+1)[x(x-3)+2(x-3)]\] \[=(x+1)(x+2)(x+3)\] Hence, the given expression can be factorised into \[3\] linear factors when\[a=0\].You need to login to perform this action.
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