A) 11 and 5
B) 1 and - 5
C) - 1 and - 5
D) - 11 and 5
Correct Answer: D
Solution :
\[2{{x}^{2}}+xy-3{{y}^{2}}+x+ay-10\] \[=(2x+3y+b)(x-y-2)\] \[=2{{x}^{2}}+xy-3{{y}^{2}}+(b-4)x-(b+6)y-2b\] Compare the coefficients of \[x,\,\,y\] and constant on both sides, we get \[b-4=1\], \[\Rightarrow \] \[b=5\] \[-(b+6)=a\], \[\Rightarrow \] \[a=-11\] and \[2b=10\] \[\Rightarrow \] \[b=5\]You need to login to perform this action.
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