A) \[\{-8,1\}\]
B) {8,1}
C) \[\text{ }\!\!\{\!\!\text{ 1},-\text{1}\}\]
D) \[\{2,-2\}\]
Correct Answer: A
Solution :
Let \[{{x}^{\frac{1}{3}}}=y\] Then \[{{y}^{2}}+y-2=0\] or \[(y+2)(y-1)=0\] or \[y=-2,\,\,1\] When \[y=-2{{x}^{\frac{1}{3}}}=-2\] or \[x=-8\] When \[y=1{{x}^{\frac{1}{3}}}=1\] or \[x=1\] Hence solution set is\[\{-8,\,\,1\}\].You need to login to perform this action.
You will be redirected in
3 sec