A) 8
B) 9
C) 10
D) 11
Correct Answer: C
Solution :
Let\[a=1.5,\,\,b=4.7\]and\[c=3.8\] \[\therefore \] Given expression \[=\frac{{{a}^{3}}+{{b}^{3}}+{{c}^{3}}-3abc}{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}-ab-bc-ca}\] \[=\frac{(a+b+c)({{a}^{2}}+{{b}^{2}}+{{c}^{2}}-ab-bc-ca)}{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}-ab-bc-ca}\] \[=a+b+c\] \[=1.5+4.7+3.8=10\]You need to login to perform this action.
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