A) \[x+2=5\]
B) \[x-2=0\]
C) \[2x+1=0\]
D) \[x+3=6\]
Correct Answer: B
Solution :
(a) Putting x=2 in x+2 we get \[2+2=4\ne 5\] |
(a) Putting x=2 in x - 2 we get 2 - 2 = 0 |
(c) Putting x=2 in 2x + 1 we get \[2\times 2+1=5\ne 0\] |
(d) Putting x=2 in x+3 we get \[2+3=5\ne 6\] |
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