A) \[x+1=1\]
B) \[x-1=3\]
C) \[2x+1=6\]
D) \[1\text{ }-x=5\]
Correct Answer: C
Solution :
(a) x + 1 = 1 |
\[\Rightarrow x+1-1=1-1\] |
[Subtracting 1 from both sides] |
\[\Rightarrow x=0\], which is an integer |
(a) \[x-1=3\] |
\[\Rightarrow x-1+1=3+1\] |
[Adding 1 to both sides] |
\[\Rightarrow x=4\], which is an integer. |
(c) \[2x+1=6\] |
\[\Rightarrow 2x+1-1=6-1\] |
[Subtracting 1 from both sides] |
\[\Rightarrow 2x=5\] |
\[\Rightarrow \frac{2x}{2}=\frac{5}{2}.\] [Dividing both sides by 2] |
\[\Rightarrow x=\frac{5}{2},\] which is not an integer. |
(d) \[1-x=5\] |
\[\Rightarrow 1-x-1=5-1\] |
[Subtracting 1 from both sides] |
\[\Rightarrow -x=4\] |
\[\Rightarrow -(-x)=-4\] |
[Multiplying both sides by (-1)] |
\[\Rightarrow x=-4\], which is an integer. |
You need to login to perform this action.
You will be redirected in
3 sec