A) \[\therefore \]
B) \[(x-3)\]
C) \[\frac{4-x}{7-x}=\frac{2}{5}\]
D) \[20-5x=14-2x\]
Correct Answer: A
Solution :
\[\frac{-{{x}^{5}}+7{{x}^{2}}-18}{{{x}^{3}}-2}\]
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