A) \[\frac{1}{x}-\frac{3}{4}+\frac{1}{2+x}=0\]
B) \[\left( 2,-\frac{3}{4} \right)\]
C) \[(5,4)\]
D) \[(-8,0)\]
Correct Answer: D
Solution :
Here, \[x=\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}\] Multiplying numerator and denominator to the right hand side by\[x=1\], we get \[y=-1\] Substituting this value for x and the given value for y in \[3x-7y=10\]we get \[xy=-1\] \[9{{x}^{2}}+49{{y}^{2}}\] Multiplying numerator and denominator to right side by \[{{(a+b)}^{3}}-{{(a-b)}^{3}}=\_\_\_\_\_.\]we have \[{{b}^{3}}+3{{a}^{2}}b\] \[2({{b}^{3}}+3{{a}^{2}}b)\]
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