A) \[f(x)=a{{x}^{2}}+bx+c\ne 0\]
B) \[3xy+7x{{y}^{2}}-8x{{y}^{3}}+7{{y}^{2}}{{x}^{2}}\]
C) \[\frac{{{a}^{3}}-3}{b}\]
D) \[\therefore \]
Correct Answer: A
Solution :
\[12x+11y=57,\] \[{{\left( \frac{{{x}^{a}}}{{{x}^{b}}} \right)}^{a+b}}\times {{\left( \frac{{{x}^{b}}}{{{x}^{c}}} \right)}^{b+c}}\times {{\left( \frac{{{x}^{c}}}{{{x}^{a}}} \right)}^{c+a}}\]\[a=\frac{1}{2-\sqrt{3}},b=\frac{1}{2+\sqrt{3},}\] [ \[{{\left( \frac{a+b}{a-b} \right)}^{2}}\]\[{{x}^{2}}-x-6=0?\] and \[(0,\frac{1}{2})\]] \[=7x=21\]
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