A) 5
B) \[\frac{1}{5}\]
C) \[-\frac{13}{17}\]
D) \[-\frac{17}{13}\]
Correct Answer: B
Solution :
Since \[x+3=x-(-3)\] is a factor of \[f(x)={{x}^{3}}+7k{{x}^{2}}-4kx+12\] \[\therefore \] \[f(-3)=0\] or \[{{(-3)}^{3}}+7k{{(-3)}^{2}}-4k(-3)+12=0\] or \[-27+63k+12k+12=0\] or \[75k-15=0\] or \[k=\frac{1}{5}\]You need to login to perform this action.
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